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Hi,<br>
websocket should listen out of the box.<br>
First, check the handbook documentation regarding WebRTC:
<a class="moz-txt-link-freetext" href="https://www.sipwise.org/doc/mr5.5.2/spce/ar01s06.html#_handling_webrtc_clients">https://www.sipwise.org/doc/mr5.5.2/spce/ar01s06.html#_handling_webrtc_clients</a><br>
<br>
Second, a good starting point is to check kamailio-lb.log and
kamailio-proxy.log:<br>
<br>
tail -f /var/log/ngcp/kamailio-lb.log<br>
<br>
tail -f /var/log/ngcp/kamailio-proxy.log<br>
<br>
<br>
And see what happens when you are dialing the number.<br>
<br>
Daniel<br>
<br>
<br>
<div class="moz-cite-prefix">On 01/08/2018 03:53 PM, Syaiful Bahri
Kamaruddin wrote:<br>
</div>
<blockquote type="cite"
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<p class="MsoNormal">Hi All,<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Need help on WebRTC, using tryit,jssip.net
, successfully connected but try to call other subscribers ,
the system said , the subscriber is not available. What should
I do, try all config on the handbook mr5.5.2.
<o:p></o:p></p>
<p class="MsoNormal">The webRTC scenario I do is webrtc to
mobile android app. So only the single subscriber I set the
configuration. How the proper config , could I done it
globally as per domain.<o:p></o:p></p>
<p class="MsoNormal">Need your great help.<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Best Regards<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Syaiful<o:p></o:p></p>
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